As in the one-dimensional case, the ratio, p, will be maximum for the matched filter, Hm(u, v). That is, p |g(xo,Yo )f p = J-— 7.2-22

is max for Hm(u, v) = K S*(u, v) exp[-j(uxo + vyo)]. Note that if s(x, y) is an even function in x and y, then S(u, v) = S*(u, v), and Hm(u, v) are real and even (i.e., they have no phase).

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