[Note that sin(au + n/4) reaches its maximum for au = n/4 rad; this broadens the low-frequency peak of Ssa(u).]
Compare the expression for Ssa(u) above with the Fourier transform of the DSF of a single ommatidium: Sj(u) = an exp(-au), for u S 0. Figure 5.2-10 plots Sj(u) and Ssa(u) vs. u. For simplicity, let a = 1° = b. Note that Ssa(u) has less low-frequency attenuation than a single ommatidium DSF, but has a zero at about u = 2.3.
To verify that the SA architecture leads to increased intensity contrast, first calculate the intensity contrast for a one-dimensional black spot of "diameter" 2r, centered on x = 0. p(x) for the spot is p(x) = I0 {1 [U(x + r) - U(x - r)]} The Fourier transform of this spot is
Was this article helpful?
This guide will help millions of people understand this condition so that they can take control of their lives and make informed decisions. The ebook covers information on a vast number of different types of neuropathy. In addition, it will be a useful resource for their families, caregivers, and health care providers.
Post a comment